原文地址：一条SQL语句搞定九九乘法表作者：永不言敗--一条语句搞定九九乘法表

select
max(case when a < 1 then '' else '1*'+cast(a as varchar)+'='+cast(a*1 as varchar) end) as [1],
max(case when a < 2 then '' else '2*'+cast(a as varchar)+'='+cast(a*2 as varchar) end) as [2],
max(case when a < 3 then '' else '3*'+cast(a as varchar)+'='+cast(a*3 as varchar) end) as [3],
max(case when a < 4 then '' else '4*'+cast(a as varchar)+'='+cast(a*4 as varchar) end) as [4],
max(case when a < 5 then '' else '5*'+cast(a as varchar)+'='+cast(a*5 as varchar) end) as [5],
max(case when a < 6 then '' else '6*'+cast(a as varchar)+'='+cast(a*6 as varchar) end) as [6],
max(case when a < 7 then '' else '7*'+cast(a as varchar)+'='+cast(a*7 as varchar) end) as [7],
max(case when a < 8 then '' else '8*'+cast(a as varchar)+'='+cast(a*8 as varchar) end) as [8],
max(case when a < 9 then '' else '9*'+cast(a as varchar)+'='+cast(a*9 as varchar) end) as [9]
from (
select 1 as a
union all
select 2
union all
select 3
union all
select 4
union all
select 5
union all
select 6
union all
select 7
union all
select 8
union all
select 9
) as t1
group by a

结果如下：